Deriving and Evaluating Expressions with One Variable

Learn what a variable is and how to evaluate expressions with one variable, like 20+5x20 + 5x. Let’s get started! 🚀

Deriving and Evaluating Expressions with One Variable - introduction visual

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Savings (£)=20+5x with x months; examples for x=1,2,3: 20+(5×1), 20+(5×2), 20+(5×3)Savings (£)=20+5x evaluated for x=8,12,20: £60=20+(5×8), £80=20+(5×12), £120=20+(5×20)Balance (£)=50−3y for y packs; examples y=1,2,3: £47=50−(3×1), £44=50−(3×2), £41=50−(3×3)Deriving and evaluating one-variable expression Balance(£)=50−3y, with y=10 giving £20 and y=15 giving £5 for £3 per pack.

🛎️ Understanding Variables

  • A variable is a letter that stands for a number that can change.
  • For example, x can represent the number of months passed.

🛎️ Understanding Expressions

  • An expression is formed by combining numbers and variables.
  • It shows how a value changes and has no equals sign.

🛎️ Forming Expressions

  • Example 1: 20 + 5x means start with 20 and add 5 for each x.
  • Example 2: 50 − 3y means start with 50 and subtract 3 for each y.

🛎️ Evaluating Expressions

  • To evaluate an expression, you replace the variable with a number.
  • You then calculate to find the value of the expression.

Practice Questions

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Deriving and evaluating expressions with one variable

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