Median, Mean, Mode and Range from a Frequency Table

The mode is the value that appears most frequently. Here, 1 appears 8 times, so the mode is 1.

The range is the difference between the maximum value (3) and the minimum value (0): $3-0=3$.

Calculate the total marks: $(10\times 2)+(20\times 3)+(30\times 4)+(40\times 1)=240$. Total frequency is $2+3+4+1=10$. Mean $=240÷10=24$.

Calculate the total number of books borrowed: $(2\times 4)+(3\times 8)+(4\times 4)=48$. Total frequency is $4+8+4=16$. Mean $=48÷16=3$.

The total number of students is $3+5+4+3=15$. The median is the 8th value. The first 3 values are 0, the next 5 values are 1, so the 8th value is 1.

First find the total frequency: $2+6+5+3=16$. Since this is even, the median is the average of the 8th and 9th values. The 8th value is 6 and the 9th value is 7, so the median is $(6+7)÷2=6.5$.