Solving Simple Quadratic Equations

To solve $x^2=25$, take the square root of both sides. Since both 5 and -5 squared give 25, the solutions are $x=5$ and $x=-5$.

The only solution is $x=0$, because $0^2=0$. The value $x=1$ is not a solution since $1^2=1$.

Since $x^2=-16$ has a negative value on the right side, there are no real solutions. The square of any real number is always zero or positive.

First isolate $x^2$ to get $x^2=64$. Taking the square root of both sides gives $|x|=8$, so the solutions are $x=8$ and $x=-8$.

Isolate $x^2$ to get $x^2=81$. Taking the square root gives $|x|=9$, so the solutions are $x=9$ and $x=-9$.

First isolate $x^2$ by adding 125 to both sides to get $5x^2=125$. Then divide by 5 to get $x^2=25$. Taking the square root gives $x=5$ and $x=-5$.